virUSBDeviceNew: Construct vroot path properly

When starting an LXC container, the /dev entries are created
under temp root (/var/run/libvirt/lxc/$name.dev), relabelled and
then the root is pivoted. However, when it comes to USB devices
which keep path to the device in the structure we need a way to
override the default /dev/usb/... path because we want to work
with the one under temp root. That's what @vroot argument is for
in virUSBDeviceNew. However, what is being passed there is:

  vroot = /var/run/libvirt/lxc/lxc_0.dev/bus/usb

Therefore, constructed path is wrong:

  dev->path = //var/run/libvirt/lxc/lxc_0.dev/bus/usb//dev/bus/usb/002/002

Signed-off-by: Michal Privoznik <mprivozn@redhat.com>
Reviewed-by: John Ferlan <jferlan@redhat.com>
This commit is contained in:
Michal Privoznik 2018-01-24 10:26:07 +01:00
parent 12ba706d6d
commit 7b0ea999fc

View File

@ -328,6 +328,7 @@ virUSBDeviceNew(unsigned int bus,
const char *vroot)
{
virUSBDevicePtr dev;
int rc;
if (VIR_ALLOC(dev) < 0)
return NULL;
@ -343,9 +344,16 @@ virUSBDeviceNew(unsigned int bus,
virUSBDeviceFree(dev);
return NULL;
}
if (virAsprintf(&dev->path, "%s" USB_DEVFS "%03d/%03d",
vroot ? vroot : "",
dev->bus, dev->dev) < 0) {
if (vroot) {
rc = virAsprintf(&dev->path, "%s/%03d/%03d",
vroot, dev->bus, dev->dev);
} else {
rc = virAsprintf(&dev->path, USB_DEVFS "%03d/%03d",
dev->bus, dev->dev);
}
if (rc < 0) {
virUSBDeviceFree(dev);
return NULL;
}