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udp: Fix 16-bit overflow in udp_invert_portmap()
The code in udp_invert_portmap() is written based on an incorrect understanding of C's (arcane) integer promotion rules. We calculate '(in_port_t)i + delta' expecting the result to be of type in_port_t (16 bits). However "small integer types" (those narrower than 'int') are always promoted to int for expressions, meaning this calculation can overrun the rdelta[] array. Fix this, and use a new intermediate for the index, to make it very clear what it's type is. We also change i to unsigned, to avoid any possible confusion from mixing signed and unsigned types. Link: https://bugs.passt.top/show_bug.cgi?id=80 Reported-by: Laurent Jacquot <jk@lutty.net> Suggested-by: Laurent Jacquot <jk@lutty.net> Signed-off-by: David Gibson <david@gibson.dropbear.id.au> Signed-off-by: Stefano Brivio <sbrivio@redhat.com>
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5
udp.c
5
udp.c
@ -258,15 +258,16 @@ void udp_portmap_clear(void)
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*/
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static void udp_invert_portmap(struct udp_port_fwd *fwd)
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{
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int i;
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unsigned int i;
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static_assert(ARRAY_SIZE(fwd->f.delta) == ARRAY_SIZE(fwd->rdelta),
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"Forward and reverse delta arrays must have same size");
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for (i = 0; i < ARRAY_SIZE(fwd->f.delta); i++) {
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in_port_t delta = fwd->f.delta[i];
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in_port_t rport = i + delta;
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if (delta)
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fwd->rdelta[(in_port_t)i + delta] = NUM_PORTS - delta;
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fwd->rdelta[rport] = NUM_PORTS - delta;
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}
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}
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